OOP_IO-2x_2023-mirror/lab3

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import java.util.Scanner;
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public class Lab5 {
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public static void main(String[] args) {
int C17 = 2430 % 17;
System.out.println("\n---------------------------------------------------------------------------------------------------------------------");
System.out.println(" C17 = " + C17 + ", So, the task is: delete all previous occurrences of the last letter of each word of the specified text");
System.out.println("---------------------------------------------------------------------------------------------------------------------");
Scanner scanner = new Scanner(System.in);
String input = null;
while (input == null || input.isEmpty()) {
System.out.print("\nEnter a string: ");
input = scanner.nextLine();
}
try {
StringBuilder sb = new StringBuilder(input);
String[] words = sb.toString().split("\\s+");
for (int i = 0; i < words.length; i++) {
String word = words[i];
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char lastChar = word.charAt(word.length() - 1);
if (!Character.isLetterOrDigit(lastChar)) {
// Last character is a punctuation mark
int lastLetterIndex = -1;
for (int j = word.length() - 2; j >= 0; j--) {
if (Character.isLetter(word.charAt(j))) {
lastLetterIndex = j;
break;
}
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}
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if (lastLetterIndex != -1) {
char lastLetter = word.charAt(lastLetterIndex);
String newWord = "";
for (int j = 0; j < word.length() - 1; j++) {
if (!Character.isLetterOrDigit(word.charAt(j)) || word.charAt(j) != lastLetter) {
newWord += word.charAt(j);
}
}
newWord += lastChar;
words[i] = newWord;
}
} else {
// Last character is a letter or a digit
char lastLetter = lastChar;
String newWord = "";
for (int j = 0; j < word.length() - 1; j++) {
if (!Character.isLetterOrDigit(word.charAt(j)) || word.charAt(j) != lastLetter) {
newWord += word.charAt(j);
}
}
newWord += lastLetter;
words[i] = newWord;
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}
}
System.out.print("\nFinal string: ");
System.out.println(String.join(" ", words));
} catch (Exception e) {
System.out.println("An error occurred: " + e.getMessage());
}
}
}
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